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Wednesday, January 8, 2020

Obeying the law (of physics)! Kinetic energy and momentum explained----make money online

Obeying the law (of physics)! Kinetic energy and momentum explained----make money online
hello in my video on crooks radiometers
i dispelled the myth that these are
actually spun around by photon pressure
and i said that if in fact photons

caused these to spin they would go the
other way because photons bouncing off
the white sides would impart momentum
and cause them to spin the other way
than they actually do but wait one of my
viewers actually said if the photons
bounce off the white veins they have a
certain amount of kinetic energy when
they come in and if they have the same
amount of kinetic energy when they come
out how could they be giving any energy
to the rotor so in today's video i'm
going to talk about kinetic energy and
momentum and if you haven't heard of a
Pelton wheel stay tuned because it's
actually a pretty cool thing
as with many physics demos we start with
an object from a science museum gift
shop this is called Newton's Cradle and
it works by lifting one of the balls on
one side giving it some potential energy
and when we let it go all that potential
energy is converted into kinetic energy
and it hits and a ball will come off the
other side so I'll show you that now
pretty good and if everything were
perfect the the middle balls here
wouldn't be moving at all and so just
one in and one out so let's take a look
you might remember that kinetic energy
is one-half times the mass times the
velocity squared and velocity is a
vector quantity there is direction
associated with velocity but since its
squared this whole quantity is scalar so
the kinetic energy of a golf ball you
know is the same as the kinetic energy
of a space shuttle or whatever it
doesn't matter what direction or what
mass this is just one scalar quantity so
according to the formula if we lifted
two balls on one side like this we would
have twice the mass and when we let them
go they'll come down it will have about
the same velocity as we as just lifting
one ball and therefore will have about
twice as much kinetic energy so
therefore we could do the math and
figure out how fast this last ball is
going to come off if we have twice the
total kinetic energy we can figure out
how much quicker that last ball is going
to come off so what we should see is two
balls lifted up hitting and then this
list the last
coming off more quickly than it did the
first time so let's try it we'll pick up
- and it doesn't behave the way that I
described
we're expecting one ball to come off
this side going faster with two balls
going in on this side and you know what
do we miss here obviously the experiment
doesn't match so we must have missed
something but the equation is correct we
have more kinetic energy going in
therefore we should have more kinetic
energy coming out what's interesting is
that we need another formula to figure
out how to define this physical system
the problem is that kinetic energy alone
can't describe the full mechanics of
this situation because there is no
directionality to it since it has this
velocity squared term in here there's no
more vector information so what we have
to add is the momentum equation and this
one is just mass times velocity but it's
not squared and since velocity is a
vector meaning it has Direction
associated with it then the momentum is
also a vector quantity let's try the
same thing again this time lifting three
balls as you can see it always works
there's always the same number of balls
on the outgoing side as the incoming
side we can even try it before in this
demo I'm going to show you that momentum
is conserved even if kinetic energy is
not so remember that total energy can't
be created or destroyed but we certainly
can convert kinetic energy into
something else and that's what I'm going
to show you right now so I have two
rubber balls here and notice that they
behave very differently that one doesn't
balance very much at all and this one
balance is quite well so to investigate
this a little further I have a force
sensor a flat piece of plastic here that
acts as a force sensor on this aluminum
bar and it's connected up to a sensing
circuit and that is connected up to the
oscilloscope and I'll do another video
talking about oscilloscope setups but
here we're just going to talk about the
physics
and when I tap on the force sensor you
can see that the oscilloscope registers
the force applied over time and I've
also set up the oscilloscope to provide
the time integral so the red line is
actually the integral of force over time
so if I just tap it very lightly you can
see that the integral becomes a steady
state value and that corresponds to sort
of the total amount of force over time
so let's drop each ball on the force
sensor and see if there's any
differences in the graphs they produce
I've set up my desk line up here so that
I drop them from the same height and
it's centered right over the force
sensor so we'll start with the non
bouncy ball okay and you can see that
the value the red line has leveled off
now let's try the bouncy ball as you can
see the red line is quite a bit higher
indicating that there was more force
applied over time to the bouncy ball now
hold on a sec you might be saying maybe
the two balls don't have the same mass
and actually you'd be correct but as it
turns out it's the non bouncy ball
that's about 20% heavier so the heavier
ball actually had a less a lower force
applied to it in this test because of
the momentum transfer so with the bouncy
ball we had this momentum coming in and
after the balance after the contact it
came shooting back off this metal plate
therefore there was more momentum
imparted to the ball by the the table
the metal block and the earth and that
caused that required more force to be
pushed into the ball whereas the non
bouncy ball came down and stopped and
there was a very small rebound which
means that less force was put into the
ball to push it back up into the air now
the masses are pretty close and so
dropping him from this height means that
both of these have about the same
kinetic energy when they hit and yet one
of them had more momentum coming out so
where'd the kinetic energy go well the
non valancy ball converted it to heat
the bouncy ball retained most of the
energy
you know it came in with about the same
kinetic energy as it left with but the
non bouncy ball see here the non bouncy
ball converts it mostly to heat and so
if we did this experiment a hundred
times or maybe even a thousand times we
notice that the non bouncy ball is a
slightly warmer after doing this because
it's converting more of that kinetic
energy to heat and another clue you
notice that the sound of impact is
different the non bouncy ball has a much
sharper louder impact sound and that
gives you another clue that more energy
is being converted from kinetic energy
into something else and in this case
sound waves another thing to notice is
that in the bouncy ball case the
incoming speed was about the same as the
outgoing speed after the collision and
this is a consequence of how the
momentum rules work so if you've ever
seen a rubber ball bouncing out into the
street and then hit by a moving car
you'll know that the ball actually comes
off from the car faster than the car was
going in fact it will be about twice the
cars speed because the car is much more
massive than the rubber ball and so all
that momentum transfer will go into the
rubber ball and it will actually be
going twice the speed it's just how the
equation comes out however remember that
motion is relative so if you're standing
on the street it looks like the ball is
going twice as fast as the car however
if you're in the car it looks like the
ball was approaching you at a speed that
is half and then after the collision
it's receding away at a speed that was
half as what you deserve-- observe on
the ground okay so now we know that a
bouncing object will impart more force
to the thing that it hit and that's
because momentum is conserved and so if
this object is coming in and hits the
table and then bounces off that means
that the table did more pushing in order
to get this moving in the opposite
direction so remember it's a vector
quantity so if this is considered the
negative direction and now suddenly it's
going positive that means there had to
have been an equal amount of force from
this other object the earth the table
everything in this room to push it back
the other way
knowing this an inventor came up with a
clever way to make water wheels more
efficient so a conventional water wheel
just think of an old wooden you know
sort of standard old
water wheel has flat blades like this
and just the current of the water going
across the river pushes on the blade and
makes the water wheel turn or similarly
the water might run down the side of the
wheel and the gravity will pull the
water down the wheel and make it turn a
Pelton wheel has veins that are shaped
like a cup and there's a jet so that the
water is channeled into like a firehose
jet and the jet sprays the water into
the curved vane and the curved plane
turns the direction of the water around
so there's a great way to visualize this
head over to the kitchen and get
yourself a spoon that has a rounded
bottom like a measuring spoon and put it
under your sink faucet and turn the
faucet on and you'll see you can
actually feel that when you put the
spoon right side up the water changing
direction will cause the spoon to be
pushed much more firmly than if you turn
the spoon upside down and the water just
runs over the back side of the spoon as
you can feel with your own hand
changing the water's direction requires
more force now here's where it gets
interesting let's zoom in on just this
part of the Pelton wheel and I'll
explain where some of the confusion came
from so this is the the cup shaped part
of the Pelton wheel and this is the jet
of water and we're going to be shooting
the water in at speed V at velocity V
and that speed is measured relative to
the nozzles so this is not moving but
the Pelton wheel is moving and if you go
to the Wikipedia page it says that the
optimum speed for this whole system is
such that the the Pelton wheel bucket is
moving with an instantaneous linear
velocity of V over 2 so half the water
speed and we'll talk about that in just
a minute but what this means is that if
the Pelton wheel is moving away from
here at V over 2 and the water is coming
in at V that means that you know the
bucket is sort of running away from the
water stream as its shooting in and so
even if this thing is turning around if
it comes off at the speed that it went
into the bucket
remember the bucket is running away from
it so ideally the water is not moving
relative to the to the nozzle but it is
moving relative to the bucket so it's
coming
from the buckets point of view the water
is coming in at V over two and it's
leaving at negative V over two so we
have the same situation with the
bouncing ball it came in at the same
speed that it left if everything is
perfect however from the water jets
perspective the water is going in at V
and it's coming out at zero the reason
that I bring this up is that if you
approach this from a kinetic energy
standpoint you could say well this is
this is the ideal case because we have
energy coming in one-half MV squared and
the water is stopped when it's gone
through our apparatus therefore we've
extracted all of the kinetic energy from
the water this is true this is all
absolutely true and so this is the most
ideal case we extract the most energy
from them from the moving water it's
also true that looking at it from a
momentum case the water is leaving at
the same speed that it came in relative
to the bucket it's just that the bucket
happens to be moving and so it makes
this situation a little bit more
complicated let's talk for a moment why
the optimum speed is V over 2 if the
bucket were locked let's say we put a
pin in the rotor so that the whole
Pelton wheel couldn't spin we still have
the the water coming in at V and in this
case it would be leaving it negative V
since the bucket is locked here and we
have this system - such that the water
always leaves at the same speed it's
coming in and we'd be delivering a lot
more force since you know we still have
this momentum transfer thing going on
that would be pushing very hard on the
bucket but how much work would it be
doing zero actually because if the rotor
is not moving it can't do anything it
can't grind our flour or produce
electricity or whatever okay so that's
not going to work we're getting zero
work out of that even though we're
getting the maximum force
conversely let's say the bucket was
moving at speed V so it's running away
from the water stream at the speed the
water is going how much force would it
be producing in that case it would be
zero because you know the water doesn't
have a chance to push against the bucket
because the bucket is already running
away at the speed of the water jet so
the water doesn't really have any
ability to push on it any in both of
these extreme cases we're not getting
any work done out of the water because
either we have no
speed in one case and we have no torque
in the other case and as it happens the
ideal speed is halfway it's V over two
and I don't think I'm going to go into
the math derivations for that but but
this is the ideal speed to get the most
work out of the water okay and so now we
come to the radiometer itself remember
isn't it is not the photons that make
this spin but there is such a thing as
light pressure so in a perfect vacuum
with enough light you could make it spin
due to photon pressure and what's
happening is when the photons hit the
black side of the veins that kinetic
energy is converted into thermal energy
just like with the non bouncy ball and
when the light hits the reflective vein
the photons that are reflected off in
part more momentum or force on that vein
which would cause the rotor to spin with
the lighter veins trailing so now we
have to figure out how much momentum we
get from the photons well we know that
momentum is mass times velocity oops I
mean photons are massless therefore they
have no momentum well not so fast the
trick is that photons do have momentum
because they're going fast enough for
they have a relativistic mass and we can
calculate that with a relatively simple
thing but I'm not going to go into it
right now we should have the same issue
that we had with the Pelton wheel so if
the rotor is locked we're actually
holding it fixed and the photons are
bouncing off the white veins they're
imparting a force and we should be able
to measure that force but are they doing
any work no because the rotor is locked
we're not actually getting any work out
of the system when we allow the rotor to
spin we actually will be extracting a
small amount of energy from the photons
and I haven't done the math myself but I
suspect that the moving the moving vane
will actually redshift the photons very
very slightly and that's probably how
the energy is extracted this is a bit of
a guess on my part so I'd be curious to
hear what you think about this okay hope
you found that enjoyable see you next

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